Given,
The focal length, f=10 cm
The distance of the object, u=20 cm
From the mirror formula,
![(1)/(f)=(1)/(u)+(1)/(v)](https://img.qammunity.org/2023/formulas/physics/college/txbbcxmux9raelx50xjsbfzcj7n8suxie9.png)
Where v is the image distance.
On substituting the known values,
![\begin{gathered} (1)/(10)=(1)/(20)+(1)/(v) \\ (1)/(v)=(1)/(10)-(1)/(20) \\ =0.05 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/e16es6x5cwjhrrtoyffvnq5nz9e4ydat0z.png)
Thus,
![v=20\text{ cm}](https://img.qammunity.org/2023/formulas/physics/college/civz494puyjv7crxlul2t0kdoyx9ysz4fl.png)
The magnification is given by,
![m=(-v)/(u)](https://img.qammunity.org/2023/formulas/physics/college/wrsz00fmtt0caizmj9cdrtm5uy4ylwctj3.png)
On substituting the known values,
![\begin{gathered} m=(-20)/(10) \\ =-2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/n2xar3d8x7zwv5xv49r6so3w17hp0dhsbs.png)
Thus the image produced is inverted.
Thus the given statement is false.