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Graph the line with slope -2/3passing through the point (5, -5).

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First, we compute the equation of the line that passes through (5,-5) and has slope -2/3 using the slope-point formula:


y-(-5)=-(2)/(3)(x-5)\text{.}

Solving for y we get:


\begin{gathered} y=-(2)/(3)x+(10)/(3)-5, \\ y=-(2)/(3)x-(5)/(3)\text{.} \end{gathered}

Therefore, (0,-5/3) is the y-intercept of the line.

Answer:

Graph the line with slope -2/3passing through the point (5, -5).-example-1
User Peter Farmer
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