Problem
Jada earned $50 babysitting and plans to use the money to go to the fair. Admission to the fair is $5 and each ride is $2.50. While at the fair, she buys a funnel cake for $3. What is the maximum number of rides Jada can ride?
Solution
For this case the total amount earned is 50$ but she buys a funnel cake for $2 so then she have remaining :
50-3=47$
Then we know that the admission fair is $5 and each ride costs $2.50 so we can create the following equation:
47 = 5 + 2.5x
Where x represent the number of rides, and if we solve for x we got:
42= 2.5 x
x= 42/2.5= 16.8
So then we can conclude that the maximum rides for this case would be 16