Question

If the frequency of an oscillator is 9.4 Hz, calculate the tie period T

Answer 1

Answer:

The period, T = 0.106 seconds

Step-by-step explanation:

The frequency, F = 9.4 Hz

Let the period be represented by T

The relationship between frequency and period is given as:

`T=(1)/(F)`

Substitute F = 9.4 Hz into the relationship above

`\begin{gathered} T=(1)/(9.4) \\ T=0.106\text{ seconds} \end{gathered}`

Therefore, the period, T = 0.106 seconds