Question

Can i some get some help?

Answer 1

According to the given information, we have

`\begin{gathered} h=-3 \\ k=5 \\ x=0 \\ y=14 \end{gathered}`

To find the vertex form, we have to find a

`\begin{gathered} y=a(x-h)^2+k \\ 14=a(0-(-3))^2+5 \\ 14-5=9a \\ a=(9)/(9)=1 \end{gathered}`

Hence, the vertex form is

`y=(x+3)^2+5`

The standard form is obtained by developing the square power

`\begin{gathered} y=x^2+6x+9+5 \\ y=x^2+6x+14 \end{gathered}`

Hence, the standard form is

`y=x^2+6x+14`