Question

Hello this is from a PowerPoint could you explain/work it for me? I’m going to be doing a worksheet soon and I need to make sure I understand it fully.

Answer 1

R2 = 2R1

The range of the second projectile is two times the range of the first projectile.

Step-by-step explanation

The gun is always in the same position and two projetiles are fired at different speeds:

Because the gun is in the same position above the floor and for both projectiles the initial vertical speed is 0 both projectiles are in the air the same time t.

The range for each projectile is

`\begin{gathered} R_1=v_(o1)t \\ R_2=v_(o2)t \end{gathered}`

And we know that the speed of the second projectile is twice the speed of the first projectile:

`v_(o2)=2v_(o1)`

Replace this into the equation of the range of the second projectile

`R_2=2v_(o1)t`

And note that next to the 2 coefficient there's the equation for the range of projectile 1:

`R_2=2R_1`

Therefore the range of the second projectile is two times the range of the first projectile.