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What mass of aspirin (C₉H₈O₄) is produced from 59.0 g of C₇H₆O₃ assuming 95.0% yield from the reaction below?C₇H₆O₃ (s) + C₄H₆O₃ (s) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).

User Nick Baker
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Answer

mass of aspirin (C₉H₈O₄) that will be produced = 73.11 g

Step-by-step explanation

Given:

balanced equation: C₇H₆O₃ (s) + C₄H₆O₃ (s) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).

mass of C₇H₆O₃ = 59.0 g

What we know:

Molar mass of C₉H₈O₄ = 180,158 g/mol

Molar mass of C₇H₆O₃ = 138,121 g/mol

Solution:

Step 1: Find the moles of C₇H₆O₃

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 59.0 g/138,121 g/mol

n = 0.427 mol

Step 2: Use stoichiometry to find moles of C₉H₈O₄

Molar ratio is 1:1

therefore moles of C₉H₈O₄, n = 0.427 mol

Step 3: Find the mass of aspirin

m = n x M

m = 0.427 mol x 180,158 g/mol

m = 76.96 g

Assume 95.0% yield from the reaction

m = 76.96 x 0.95 = 73.11 g

User Jarnohenneman
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