Question

3÷2+45-90×100+2021÷2001=

Answer 1

Step-by-step explanation:

First we have to separate this expression in terms. The terms are delimited by + or - signs. I'll add parenthesis to separate the terms:

`(3/2)+(45)-(90*100)+(2021/2001)`

Now we have to solve the expressions inside each parenthesis first:

`((3)/(2))+(45)-(9000)+((2021)/(2001))`

We have fractions in this expression. To do the additions and substractions we have to find the lowest common denomination. Since the denominators we have are 2 and 2001, and 2001 is not divisible by 2, the lowest common denominator is 2001x2=4002:

`\begin{gathered} (3)/(2)+45-9000+(2021)/(2001) \\ (3*2001+45*4002-9000*4002+2*2021)/(4002) \end{gathered}`

Now we have to separate the terms again for the numerator:

`((3*2001)+(45*4002)-(9000*4002)+(2*2021))/(4002)`

And solve what's inside each parenthesis:

`((6,003)+(180,090)-(36,018,000)+(4,042))/(4,002)`

And add:

`(-35,827,865)/(4,002)=-8,952.49`

Answer:

3÷2+45-90×100+2021÷2001 =​ -8952.49