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A student wishes to prepare 25mL of 0.1M NaOH from 6M NaOH. How many mL of 6M NaOH need to be placed in a 25.00mL volumetric flask for dilution to generate 25mL of a 0.1M solution?
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A student wishes to prepare 25mL of 0.1M NaOH from 6M NaOH.

How many mL of 6M NaOH need to be placed in a 25.00mL volumetric flask for dilution to generate
25mL of a 0.1M solution?

User AJReading
by
4.9k points

1 Answer

3 votes

Answer:

Na(OH)4

Step-by-step explanation:

Look at the charges and add them up

Na(OH) Na(OH)

User Durwin
by
5.1k points
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