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A line passes through the point (-8,5) and has a slope of -3.Write an equation in slope-intercept form for this line.

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ANSWER


y=-3x-19

Step-by-step explanation

We want to find the equation of the line that passes through the point and has the given slope.

The -intercept form of the equation of a straight line is given by:


y=mx+b

where m = slope

b = y-intercept

To find the equation, we have to apply the point-slope method:


y-y_1=m(x-x_1)

where (x1, y1) is the point the line passes through.

Hence, the equation of the line in slope-intercept form is:


\begin{gathered} y-5=-3(x-(-8)) \\ y-5=-3(x+8) \\ y-5=-3x-24 \\ y=-3x-24+5 \\ y=-3x-19 \end{gathered}

That is the answer.

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