Question

Using the graph to the right , write the ratio in simplest form. AC/BC

Answer 1

Answer:

AC/BC = 11 / 5

Explanations:

To find the ratio AC / BC

Step 1: Identify the coordinates of A, B and C

A ( -5, 0), B( 1, 0), C(6, 0)

Step 2: Find the distance AC and BC

`\begin{gathered} Dis\tan ce\text{ betw}een\text{ two points is calculated with the formula:} \\ D\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}^{} \end{gathered}`

For the distance AC:

A ( -5, 0), C(6, 0)

`\begin{gathered} x_1=-5,y_1=0,x_2=6,y_2=0 \\ AC\text{ = }\sqrt[]{(6-(-5))^2+(0-0)^2^{}} \\ AC\text{ = }\sqrt[]{(6+5)^2} \\ AC\text{ = }\sqrt[]{11^2} \\ AC\text{ = 11} \end{gathered}`

For the distance BC:

B( 1, 0), C(6, 0)

`\begin{gathered} x_1=1,y_1=0,x_2=6,y_2=0 \\ BC\text{ = }\sqrt[]{(6-1)^2+(0-0)^2} \\ BC\text{ = }\sqrt[]{5^2} \\ BC\text{ = 5} \end{gathered}`

AC/BC = 11 / 5