Question

A cubical block of concrete edge 0.30 m, rests on a horizontal surface. If its weight is 240N, what pressure does it exert on the surface?

Answer 1

The pressure exerted by the cubical block of concrete on the surface is approximately 2666.67 Pa.

Step-by-step explanation:

To find the pressure exerted by a cubical block of concrete on a surface, we can use the formula:

Pressure = Weight / Area

Given that the weight of the block is 240N and the edge length is 0.30m, we can calculate the area of one face of the cube as:

Area = (Edge length) x (Edge length)

Substituting the values, we get:

Area = 0.30m x 0.30m = 0.09m²

Now we can substitute the values into the pressure formula:

Pressure = 240N / 0.09m²

Calculating this, we find that the pressure exerted by the block on the surface is approximately 2666.67 Pa.

Answer 2

`\begin{gathered} Given:\text{ edge lenght= 0.30m} \\ so\text{ the area of the bottom surface= 0.30m*0.30m } \\ A=0.09m^2 \\ and\text{ this is also the area of horizontal surface.} \\ weight=240N \\ \text{ pressure exerted by the cube on the horizontal surface=?} \\ \end{gathered}`
`\begin{gathered} pressure\text{ is given by the following formula-} \\ P=(F)/(A) \\ Here\text{ P is pressure acting on the surface.} \\ F=\text{ Force acting on the surface} \\ A=\text{ Area of the surface.} \end{gathered}`
`\begin{gathered} here\text{ force acting on the surface = 240N in downward direction} \\ putting\text{ all the values in the formula } \\ P=(240N)/(0.09m^2) \\ P=2666.67\text{ N/m}^2 \end{gathered}`

So the pressure exerted by the cube on the surface is 2666.67N/m^2 in the downward direction.

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