Question

A force of 80N acts on a current carrying conductor 80cm long at 30 to a magnetic field of flux density 0.50T. Calculate the current flowing

Answer 1

Given that the force is F = 80 N

The length of the conductor is L = 80 cm = 0.8 m

The magnetic field of flux density is B = 0.5 T

The angle is 30 degrees.

We have to find the current in the circuit.

The current in the circuit will be

`\begin{gathered} F=IBLsin30^(\circ) \\ I=\frac{F}{\text{BLsin}30^(\circ)} \\ =(80)/(0.5*0.8*0.5) \\ =\text{ 400 A} \end{gathered}`

The current in the circuit will be 400 A