Let's evaluate the given Trigonometric functions and find the exact value.
Question A:

Question B:
cos 225°
To find the exact value of cos 225°, apply the reference angle by finding the angle in the first quadrant with equivalent values.
Thus, we have:
225 - 90 - 90 = 45°
Make the expression negative because cosine is negative in the third quadrant.
We have:
![\begin{gathered} -\cos 45\degree \\ \\ \text{The exact value of cos45}\degree\text{ is }\frac{\sqrt[]{2}}{2} \\ \\ -\cos 225\degree=-\frac{\sqrt[]{2}}{2}=-0.707 \\ \\ -\cos 225\degree=-0.707 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4fdpxmnfipkrmt4up8l90ppylaob97n1ot.png)
ANSWER:
![\begin{gathered} Question\text{ A: }(1)/(2) \\ \\ \text{Question B: }\frac{\sqrt[]{2}}{2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/405g3fdtj3trcbsp7e0gn6l4sf2zyb06gq.png)