Given:
Initial velocity = 11 m/s
Average acceleration = -1.81 m/s²
Let's determine how long it takes the horse to decrease its velocity to 6.5 m/s.
Apply the equation of motion:
![v=u+at](https://img.qammunity.org/2023/formulas/mathematics/high-school/noa8ap485tcbqe59xpwvgja2yjtndl0d9d.png)
Where:
v is the final velocity = 6.5 m/s
u is the initial velocity = 11 m/s
a is the acceleration = -1.81 m/s²
t is the time in seconds.
Thus, we have:
![\begin{gathered} 6.5=11+(-1.81)t \\ \\ 6.5=11-1.81t \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/699hyucsuu00wxtas1cv9bh2784oqmfw3j.png)
Let's solve for t.
Subtract 11 from both sides:
![\begin{gathered} 6.5-11=11-11-1.81t \\ \\ -4.5=-1.81t \\ \\ \text{Divide both sides by -1.81:} \\ (-4.5)/(-1.81)=(-1.81t)/(-1.81) \\ \\ 2.49=t \\ \\ t=2.49\text{ seconds} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/eg0421l0s16w0ux0f66gaovv38gsqriak7.png)
Therefore, it took the horse approximately 2.49 seconds to decrease its velocity to 6.5 m/s
ANSWER:
2.49 seconds.