106k views
3 votes
How does the estimated value compare to the actual value from the table when x is 2.3?

How does the estimated value compare to the actual value from the table when x is-example-1
User Geon
by
8.1k points

2 Answers

5 votes

The estimated value is 0.013084 smaller than the actual value.

A function is described in this table. We have an output, y, for every input, x. With those points, we can use a linear regression calculator to get the following line equation.

y = -2.45138x + 11.82509

When we calculate x = 2.3 in our line, we get

y(2.3) = -2.45138 (2.30 + 11.82509

= 6.186916

Given that y = 6.2 for x = 2.3 is the result on the table, the discrepancy between the estimated and actual values is

6.2 - 6.186916 = 0.013084

The difference between the estimated and actual values is 0.013084.

User Alex Dowining
by
8.2k points
2 votes

This table describes a function. For each input x we have an output y. Using a linear regression calculator with those points, we get the following line equation


y=-2.45138x+11.82509

Evaluating x = 2.3 in our line, we have


y(2.3)=-2.45138\cdot2.3+11.82509=6.186916

The result on the table is y = 6.2 for x = 2.3, therefore, the difference between the estimated value and the actual value is


6.2-6.186916=0.013084

The estimated value is 0.013084 smaller than the actual value.

User Delevoye Guillaume
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.