73.6k views
1 vote
xThe object above is symmetrical through Z. If Y = 19 inches, Z = 21 inches, and H = 10 inches, what is the area of the object?A. 420 square inchesB. 210 square inchesC. 57 square inches

xThe object above is symmetrical through Z. If Y = 19 inches, Z = 21 inches, and H-example-1
User Unis
by
5.3k points

1 Answer

3 votes

hello

to solve this question, we have to take the object part by part and solve for the area and the add them up together.

we can solve for x using pythagoran theorem


\begin{gathered} 19^2=10^2+x^2 \\ x^2=19^2-10^2 \\ x^2=361-100 \\ x^2=261 \\ x=\sqrt[]{261} \\ x=16.16 \end{gathered}

since we know the

xThe object above is symmetrical through Z. If Y = 19 inches, Z = 21 inches, and H-example-1
User Christopher Chiche
by
5.3k points