Question

Write the polynomial as a product of a difference and a sum: b^2-4/9

Answer 1

`\sf \huge \boxed{ \boxed{(b + (2)/(3) )(b - (2)/(3) )}}`

Explanation:

to understand this

you need to know about:

• algebra
• PEMDAS

tips and formulas:

• 
  `{x}^(2) - {y}^(2) = (x + y)(x - y)`

let's solve:

1. 
   `\sf \: rewrite : \\ ( {b})^(2) - ( (2)/(3) {)}^(2)`
2. 
   `\sf use \: the \: formula : \\ (b + (2)/(3) )(b - (2)/(3) )`

Answer 2

Solution given:

`b^(2) -(4)/(9)`=
`b^(2) -(2^2)/(3^2)=b^2 -((2)/(3))^2`

it is in the form of x²-y²=(x+y)(x-y)

so

`b^2 -((2)/(3))^2=(b+(2)/(3))(b-(2)/(3))` is A required polynomial.

Explanation: