Given:
A circle with the equation:
![x^2+y^2\text{ = 9}](https://img.qammunity.org/2023/formulas/mathematics/college/5d2r1qbbhihoqjs0ziotwym9admlgkpo1m.png)
Solution
Recall that the general equation of a circle is of the form:
![(x-a)^2+(y-b)^2=r^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/ilekd9w5v3ytefhk3unvr8rhka2u3mptc6.png)
Where (a, b) are coordinates of the center and r is the radius of the circle.
Re-writing the given equation using the general form gives us:
![(x-0)^2+(y-0)^2=3^2](https://img.qammunity.org/2023/formulas/mathematics/college/be6ch2568puiav435tic4k78l8bcdtmm9u.png)
Hence, the center and radius of the circle are (0, 0) and 3 respectively.
The graph of the equation is shown below:
The graph is obtained by first locating the center of the circle (0,0) on the graph. Then, we measure 3 units from the center to construct the required circle.