To solve this problem we need to use the compound interest formula:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
Where P is the initial deposit:
![P=700](https://img.qammunity.org/2023/formulas/mathematics/college/q6kcn8bmt8c0sdfyvbso6z0n0u4au20w3w.png)
r is the interest rate in decimal form, since the interest rate is 11%, in the decimal form we have:
![r=0.11](https://img.qammunity.org/2023/formulas/mathematics/college/eeym84qosn6xzk1azpitztahw7un6l0k3i.png)
n is the number of times that the interest is compounded in a year, in this case, it is compounded quarterly, and since there are 3 quarters in a year, the interest will be compounded 3 times per year:
![n=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/7u13nv5v7w6dm53vjt67muumez9vorpsq0.png)
and t is the total time, in this case, 3 years:
![t=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/ezng7l9uqlvz8ytysjg03bfv39poyo7ap5.png)
Substituting all of these values into the formula to find the Amount "A" they will have after 3 years:
![A=700(1+(0.11)/(3))^(3\cdot3)](https://img.qammunity.org/2023/formulas/mathematics/college/qyzfbpximqnaus1pcvidtrwzgopau7ot68.png)
Solving the operations:
![A=700(1+0.03666)^9](https://img.qammunity.org/2023/formulas/mathematics/college/zywzj9cbb90t9tv3gzq7bu0vdt545jh4f3.png)
![A=700(1.03666)^9](https://img.qammunity.org/2023/formulas/mathematics/college/36p8daexc0dmzw8e22bfnnqkjlrg2f1sky.png)
![A=700(1.382777)](https://img.qammunity.org/2023/formulas/mathematics/college/5enoqvl3z5nh5jfanl14yuekvaw46jm534.png)
![A=967.944](https://img.qammunity.org/2023/formulas/mathematics/college/e5clljj5l27x9rgiyvfy40md16yb263v8v.png)
Answer: They will have $967.944 to spend