Solution
Step 1
Write an expression for the probability of an event

No of the required events can be found with the following table
The numbers(1,2,3,4,5,6) on the vertical are for one dice and the others on the horizontal are for the second dice
No of required of numbers on both dices less than 5 are : 1,1 1,2 1,3 1,4 2,1 2,2 2,3 2,4 3,1 3,2 3,3 3,3 3,4 4,1 4,2 4,3 4,4. The number of the events are therefore, = 16
No of total events = 36
Step 2
Substitute the values and find the required probability
