To write the equation;
in standard form, we will follow the steps below:
From the above
a=1
b=4
c=7
So find (b/2a)²
=[4/2(1)]²
=(4/2)²
=2²
=4
We will now have;
y = (x²+4x+4) + 7-4
y=(x+2)² +3
comparing with;
y=a(x-h)² + k
h=-2
k=3
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