Answer:
![P\text{ = 0.992 atm}](https://img.qammunity.org/2023/formulas/chemistry/college/6w651r69ypghled4jzck5xmsifahv3ly08.png)
Step-by-step explanation:
Here, we want to get the pressure occupied by the gas under the given conditions
We can use the ideal gas equation here
Mathematically, we have this as:
![PV\text{ = nRT}](https://img.qammunity.org/2023/formulas/chemistry/college/g81ctptk67jgtk1ac4lk1fo6h7jipxl4ti.png)
P is the pressure which we want to calculate
V is the volume occupied by the gas given as 42.5 L
n is the number of moles, given as 1.52 moles
R is the molar gas constant which is :
![R\text{ = }0.082057LatmK^(-1)mol^(-1)](https://img.qammunity.org/2023/formulas/chemistry/college/yxlx09urzm4wofslk3fh29m1ufxk6oildh.png)
T is the temperature which we have to convert to absolute temperature scale (Kelvin) by adding 273.15 K to the Celsius temperature
![273.15\text{ + 65 = 338.15 K}](https://img.qammunity.org/2023/formulas/chemistry/college/emzdzmag0nru07578vg2vt4kl3378c6c82.png)
Let us rewrite the equation in terms of the Pressure, which we want to calculate
We have this as:
![P\text{ = }(nRT)/(V)](https://img.qammunity.org/2023/formulas/chemistry/college/1x7677qkvwqlc1sdii1wfucw5zp75oyrpu.png)
Finally, we proceed to substitute the values given above:
![\begin{gathered} P\text{ = }\frac{1.52\text{ }*0.082057*338.15}{42.5} \\ \\ P\text{ = 0.992 atm} \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/c3pxa4upy8c1ktj8bmuc5j3iru8myawunr.png)