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Find the solution set of each linear system. Identify inconsistent systems and dependent equations.3x+2y+z= 8x+y+2z=44x+y+z= 7

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We are given three set of system equations with three unknowns

3x + 2y + z = 8 --------- equation 1

x + y + 2z = 4------------- equation 2

4x + y + z = 7 ------------- equation 3

Firstly, we need to eliminate a single variable, so that we can solve the remiaining equations simultaneously

Let us eliminate z in equation 1 and 2

3x + 2y + z = 8

x + 2y + 2z = 4

To eliminate z, multiply equation 1 by 2 and equation 2 by 1

3x *2 + 2y * 2 + 2*z = 8*2

x*1 + 2y*1 + 2z*1 = 4*1

6x + 4y + 2z = 16

x + 2y +2z = 4

Substract the last equation from the first equation

6x - x + 4y - 2y + 2z -2z = 16 - 4

5x + 2y + 0 = 12

5x + 2y = 12 ------- equation 4

Secondly, combine equation 1 and 3 together

3x + 2y + z = 8

4x + y + z = 7

Substract the last equation from the first equation

3x - 4x + 2y - y + z - z = 8 - 7

-x + y + 0 = 1

-x + y = 1 ---------- equation 5

Solve equation 4 and 5 simultaneously

5x + 2y = 12

-x + y = 1

Let us eliminate y first

To eliminate y, multiply equation 1 by 1 and equation2 by 2

5x * 1 + 2y *1 = 12*1

-2x + 2 *y = 1 *2

5x + 2y = 12----------- 6

-2x + 2y = 2 ----------- 7

Substract equation 7 from 6

5x - (-2x) + 2y - 2y = 12 - 2

5x + 2x + 0 = 10

7x + 0 = 10

7x = 10

Divide both sides by 7

7x /7 = 10/7

x = 10/7

To find y, substitute the value of x into equation 6

-x + y = 1

-10/7 + y = 1

Make y the subject of the formula

y = 1 + 10/7

y = 7 x 1/1 + 7 x 10/7 / 7

y = 7 + 10/7

y = 17/7

To find z, substitute the values of x and y into equation 2

X + y + 2z = 4

10/7 + 17/7 + 2z = 4

= 10/7 + 17/7

= 27/7

27/7 + 2z = 4

Collect the like terms

2z = 4 - 27/7

2z = 4 * 7 /1 - 27 *7/7 / 7

2z = 28 - 27 / 7

2z = 1/7

Divide both sides by 2

2z/2 = 1/7 /2

z = 1/14

The solution of the equations are

x = 10/7, y = 17/7 and z = 1/14

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