Question

A football player kicked a ball at an angle of 37o above the horizontal with an initial velocity of 20 m/s, what is the maximum height reached by the ball? a. 62 m b. 26 m c. 7.4 m d. 5.1 m

Answer 1

H = 8.45 m

Step-by-step explanation:

Given that,

Angle of projection,
`\theta=37^(\circ)`

The initial velocity of the ball, u = 20 m/s

We need to find the maximum height reached by the ball. The formula for the maximum height is given by :

`H=(u^2\sin^2\theta)/(2g)\\\\H=((20)^2* \sin^2(37))/(2* 9.8)\\\\H=8.45\ m`

So, the maximum height reached by the ball is 8.45 m.