Question

During a sprint, a basketball player is traveling at +3 m/s. Four seconds later, the player is traveling at –5 m/s. The average acceleration of the basketball player over the last 4 seconds is:

Answer 1

the average acceleration of the basketball player over the last 4 seconds is 0.5 m/sec^2

Explanation:

The computation of the average acceleration is shown below:

= Change in velocity ÷ change in time

= 5 - 3 ÷ 4

= 2 ÷ 4

= 0.5 m/sec ^2

Hence, the average acceleration of the basketball player over the last 4 seconds is 0.5 m/sec^2