SOLUTION
From the question the height of the can is 4 ft and its diameter is 1.5 ft
The radius r of the can since it is shaped like a cylinder is

The quantity or the contents of the container is the volume V of a cylinder, which is

Now, we are told that the average weight of aluminium cans is 37 ounces per cubic feet.
This means that 1 cubic feet of aluminium weighs 37 ounces. But the contents is approximately 7.1 cubic feet. Hence 7.1 cubic feet of aluminium will weigh

Hence the answer is approximately 262.7 ounces