397,240 views
42 votes
42 votes
PLEASE HELP ME!!
write three to the power of two sevenths in radical form and explain?

User Upen
by
2.9k points

2 Answers

8 votes
8 votes

Answer:


\sqrt[7]{3^(2)}

Explanation:


3^(2/7)

^ That is 3 to the 2/7ths power. We know that. Now it needs to be in radical form. That takes a bit of thinking.

If you have a power that is less than one (like 1/2) it is can be written as a root. So say you're given
2^(1/2). That is the same exact thing as saying
√(2). It's the same thing. You can say it either way.

In the same way, a squared power, like
2^(2), is the same as representing it like a fraction, like
2^(2/1). They both mean the same thing.

So by pointing these out, a fraction power = the power / the root.

If that makes sense.

So, with this in mind, let's look at what we have again.


3^(2/7)

So we can split it up to say that 3 is raised to a 2nd power times a 1/7th power.

So we know what a 3 to the 2nd power is:
3^(2).

And since we have a fraction that's also included, we now know that is a root. So we can represent that like this:
\sqrt[7]{3}.

But those two answers need to be combined. We can do that like this:
\sqrt[7]{3^(2)}

Answer:
\sqrt[7]{3^(2)}

So there it is! I hope that helped you!!

User RSW
by
2.8k points
28 votes
28 votes

Answer:

4782969

Explanation:

User Houston
by
2.5k points