Question

Can anyone solve number 5 for me or help me with it

Answer 1

Step 1

Given;

`\sqrt[]{-32}`

Required; To simplify the problem

`\text{Note; }\sqrt[]{-1}=i`

Step 2

Simplify the problem

`\begin{gathered} \sqrt[]{-32}=\sqrt[]{-1}*\sqrt[]{32} \\ =\sqrt[]{32}i \end{gathered}`
`\begin{gathered} \sqrt[]{32}=\text{ }\sqrt[]{16*2} \\ \end{gathered}`
`\begin{gathered} \sqrt[]{-32}=\sqrt[]{16*2}* i \\ \sqrt[]{-32}=\sqrt[]{16}*\sqrt[]{2}* i \\ \sqrt[]{-32}=4*\sqrt[]{2}* i \\ \sqrt[]{-32}=4\sqrt[]{2}i \end{gathered}`