Question

Find the distance between P (2,2) and Q (5.5, 6.25)

Answer 1

distance between them is 5.51 units.

Step-by-step explanation:

`\boxed{distance =√((x2 - x1)^2+(y2-y1)^2) }`

given coordinates: P (2,2) and Q (5.5, 6.25)

using the formula:

`\boxed{distance =√((5.5 - 2)^2+(6.25-2)^2) }`

`\boxed{distance =√(12.25+18.0625) }`

`\boxed{distance =√(30.3125) }`

`\boxed{distance = 5.51 }`