Question

In the fall a farmer hopes to be able to harvest about 190 bushels per acre. A bushel of corn weighs about 56 pound. How much would the corn from a 130 acre field weigh in tons? (assume that 1 ton = 2000 pounds) . Round off to the nearest whole number

Answer 1

The weight of 130 acres of corn is:

`X\approx692\text{tons (to nearest whole number)}`

SOLUTION

Problem Statement

The question tells us a farmer wants to harvest 190 bushels for each acre of land. Each bushel of corn weighs 56 pounds and we are required to find the weight of corn from a 130 acre field in tons given that 1 ton is equivalent to 2000 pounds.

Step-by-step explanation

Step 1:

First of all, let us find the total weight of the corn in 1 acre. We are told that 1 acre contains 190 bushels and 1 bushel contains 56 pounds of corn. This means that:

If 1 bushel of corn weighs 56 pounds, then 190 bushels (equivalent to 1 acre) would be:

`56*190=10640\text{pounds}`

Step 2:

After finding the weight of 1 acre of corn, we are now best placed to find the weight of 130 acres of corn.

If 1 acrea of corn weighs 10,640 pounds, then 130 acres woudl be:

`130*10640=1,383,200\text{ pounds}`

Step 3:

We are required to find our answer in tons and to round to the nearest whole number.

We are given that:

1 ton is equivalent to 2000 pounds, this implies that:

`\begin{gathered} \text{X tons will be equivalent to 1,383,200 pounds} \\ \text{Thus, we can write:} \\ X=(1383200)/(2000) \\ \therefore X=691.6\text{ tons} \\ \\ \text{Thus, the number of tons is:} \\ X\approx692\text{tons (to nearest whole number)} \end{gathered}`

Final Answer

The weight of 130 acres of corn is:

`X\approx692\text{tons (to nearest whole number)}`