Question

What is the number of cycles of y = 4 sin(2011) + 2 between 0 and 2?

Answer 1

The given function is

`y=4sin(2\theta-(11\pi)/(6))+2`

Since the angle is 2 theta, then

That means the period is pi instead of pi/2

That means we have 2 cycles from 0 to 2pi

The correct answer is D