Given that:
- The recipe calls for this amount of flour for 3 dozen cookies:
![(7)/(6)cup](https://img.qammunity.org/2023/formulas/mathematics/college/exmf81yme8hmv4sctsqrjmbjavk6ba3asd.png)
- Cassandra plans to make 21 dozen​ cookies.
Let be "x" the number of cups of flour she needs to make 21 dozen​ cookies.
Using the data given in the exercise, you can set up the following proportion:
![((7)/(6))/(3)=(x)/(21)](https://img.qammunity.org/2023/formulas/mathematics/college/gseljsxok3qupdfsy9qj54lf9xzbs8tws4.png)
Now you have to solve for "x":
1. You can rewrite the expression on the left side as follows:
![(7)/(6)\cdot(1)/(3)=(x)/(21)](https://img.qammunity.org/2023/formulas/mathematics/college/3q8l5xj8hvevwxeugw49ln4g21xag4nn9u.png)
2. Simplify by multiplying the fractions on the left side:
![(7)/(18)=(x)/(21)](https://img.qammunity.org/2023/formulas/mathematics/college/ooemjjx4layi5l9auo7tzpo7tvnklqiava.png)
3. Multiply both sides of the equation by 21:
![\begin{gathered} (7)/(18)\cdot21=(x)/(21)\cdot21 \\ \\ (147)/(18)=x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/n5jz5nobayihe71vpsm5axcgc2fkd5sg0b.png)
4. You can reduce the fraction by dividing the numerator and the denominator by 3:
![\begin{gathered} (147/3)/(18/3)=x \\ \\ x=(49)/(6) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gyd5ltmref2vhv61kjnp5ri9fa1dlw6q5a.png)
Hence, the answer is:
![(49)/(6)cups](https://img.qammunity.org/2023/formulas/mathematics/college/bb2uphydzi9hwjd0oacq8202gsl1re60tf.png)