Question

15. PSAT Practice - CALCULATOR ALLOWED. Let *Y* be defined forall y by the equation *Y* = 3y+1. For example *6* will equal3(6)+1, which is 19. If *3* - *Y* = ywhat is the value for y? Enterthe number that would be bubbled in the grid.

Answer 1

y = 2.25

Step-by-step explanation:
`\begin{gathered} \text{The equation:} \\ \text{ }*Y*\text{ = 3y + 1} \end{gathered}`
`\begin{gathered} \text{when y = 6} \\ Y\text{ = 3(6) + 1} \\ Y\text{ = 18 + 1} \\ Y\text{ = 19} \end{gathered}`
`\begin{gathered} \text{when y = 3} \\ \text{The equation: } \\ *3*-*Y*=y \\ *3*\text{becomes:} \\ \text{replace y with 3} \\ \text{Y = 3(3) }+\text{ 1} \\ Y\text{ = 9 + 1} \\ Y\text{ = 10} \end{gathered}`

Inserting into the equation:

`\begin{gathered} 10\text{ - (3y + 1) = y} \\ 10\text{ - 3y - 1 = y} \\ 9\text{ - 3y = y} \\ 9\text{ = y + 3y} \\ 9\text{ = 4y} \\ y\text{ = 9/4} \\ y\text{ =2.25} \end{gathered}`