In this probelm to get a sum that is equal to 6 we have to spin and have 3 in bout spiners so: the probability to have 3 in the first one is:
1/6
and in the secon one is:
1/3
So in total there is a probability of:
![(1)/(3)\cdot(1)/(6)=(1)/(18)](https://img.qammunity.org/2023/formulas/mathematics/college/1b8ipmt2c6rgmekwqerh5m19hddytkl2it.png)
This means that each 18 time he spin the spiners one will be equal to 6 so:
However another option to get 6 is that in the first spiner you have 5 and in the second one you have 1 and the probabilities will be the same so:
![(1)/(3)\cdot(1)/(6)=(1)/(18)](https://img.qammunity.org/2023/formulas/mathematics/college/1b8ipmt2c6rgmekwqerh5m19hddytkl2it.png)
and the last chance to have 6 is if in the first spiner we get 4 and in the secon one we get 2 and the probability will be the same so:
![(1)/(3)\cdot(1)/(6)=(1)/(18)](https://img.qammunity.org/2023/formulas/mathematics/college/1b8ipmt2c6rgmekwqerh5m19hddytkl2it.png)
So the probabilitie to have 6 in the sum will be the addition of the probabilites so:
![(1)/(18)+(1)/(18)+(1)/(18)=(3)/(18)=(1)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/fvxoqgqoanxxiifr8ovr33apa2ishbz1a7.png)
So the proportion will be:
![\begin{gathered} (1)/(6)=(x)/(500) \\ x=(500)/(6) \\ x=83.3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3lcpg5waza2zzo7dzb86igxc4p0yw5buod.png)