We know that the volumen is
![v=\text{ area of the base}\cdot length(height)](https://img.qammunity.org/2023/formulas/mathematics/college/x3epspswloccv9rmqwfgdpobtnluck72bd.png)
In this case, the base is a circumferecen. So, the area of the base is
![\text{ area of the base}=\pi\cdot r^2](https://img.qammunity.org/2023/formulas/mathematics/college/q22rbw7vpk39f2g9kppqgtgqgyoajv1rdy.png)
Now, the volume of the cylindrical construction is
![v=\pi\cdot r^2\cdot length(height)](https://img.qammunity.org/2023/formulas/mathematics/college/10wi52p2n11t3mm8nt88h26ukxfo8pdzbh.png)
Where,
![\begin{gathered} \pi=3.14 \\ r=2ft\text{ is the radius of the circumference} \\ \text{length}=17ft \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/eex6yv7o67ob3j6ym756gio4zflw40pktr.png)
Replacing the values in the eqution for the volume we obtain
![v=(3.14)(2ft)^2(17ft)](https://img.qammunity.org/2023/formulas/mathematics/college/3vtevxyb1zm1b4ftkduzeyvz007n6s521o.png)
Solving the multiplications
![v=213.52ft^3](https://img.qammunity.org/2023/formulas/mathematics/college/iyrw604eegh9fiyuqkq9d3t2pltdf64t37.png)
Finally, rounding the answer to the nearest whole number
![v=213.52ft^3\approx214ft^3](https://img.qammunity.org/2023/formulas/mathematics/college/g04xjpvg6di6febmi3dbary74lxel0cpba.png)
ANSWER:
![214ft^3](https://img.qammunity.org/2023/formulas/mathematics/college/m6aas54jnyzpmn789956o7kqwgur2fgm9o.png)