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Use point-slope form to write the equation of a line that passes through the point(8, 18) with slope -7/6

User Meiying
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SOLUTION

The equation of a line in point-slope form is given by the formula


\begin{gathered} y-y_1=m(x-x_1) \\ \text{Where m = slope } \end{gathered}

From what we are given,


\begin{gathered} m=-(7)/(6) \\ x_1=8 \\ y_1=18 \end{gathered}

Substituting the values, we have


\begin{gathered} y-y_1=m(x-x_1) \\ y-18=-(7)/(6)(x-8) \\ y-18=-(7)/(6)x+(28)/(3) \\ y=-(7)/(6)x+(28)/(3)+18 \\ y=-(7)/(6)x+(82)/(3) \end{gathered}

Hence, the answer is


y=-(7)/(6)x+(82)/(3)

User Frals
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