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Y=(x−2)^2+5 → y=(x+2)^2−3A. T<4,−8>B. T<−4,8>C. T<−4,−8>D. T<4,8>
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Y=(x−2)^2+5 → y=(x+2)^2−3A. T<4,−8>B. T<−4,8>C. T<−4,−8>D. T<4,8>

User Mikelowry
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y=\left(x−2\right)^2+5→y=\left(x+2\right)^2−3

User Lry
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