Answer:
sin D = FE/DE = 13√3 /26 = √3 /2
sin E = DF/DE = 13/26 = ½
(sin E = cos D)
cos D = DF/DE = 13/26 = ½
cos E = EF/DE = 13√3 /26 = √3 /2
(sin D = cos E)
Here are what they equal in their simplest forms!
Explanation:
Sin D & Cos E were originally equal to 13 -/3 over 26
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Sin E & Cos D were originally equal to 13/26
Hope I was able to help!
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