We can follow the factors as follows:
![4p\cdot(p^2+9p+8)](https://img.qammunity.org/2023/formulas/mathematics/college/qan9he9odiwftm7c2qpnl7l27en35z3rhu.png)
We have now to factor the second-order polynomial. For this, we can use the Quadratic Formula to find the roots and then factor them, or we can try to find two numbers that:
1. If we sum them, we have 9.
2. If we multiply them, we have 8.
In this case, both numbers are 1 and 8, since:
1+8 = 9
1*8 = 8
Then, the factors are:
![4p\cdot(p+1)\cdot(p+8)](https://img.qammunity.org/2023/formulas/mathematics/college/lamt4jr5brvk60v7mg5yme0pohg2q6fhrt.png)
Therefore, the factors of the original polynomial are:
4p, (p+1) and (p + 8).