Question

At a certain college, 55% of the students are female, and 17% of the students major in civil engineering. Furthermore,8% of the students both are female and major in civil engineering.(a) What is the probability that a randomly selected civil engineering major is female? Roundyour answer to the nearest hundredth.(b) What is the probability that a randomly selected female student majors in civilengineering? Round your answer to the nearest hundredth.

Answer 1

STEP 1

Let's assume that the number of student in the college is x

Therefore the number of female students that major in civil engineering is

`(8)/(100)\text{ x X = 0.08}x`

Also, the number of students that major in civil engineer is

`(17)/(100)\text{ x X = 0.17X}`

a)The probability that a randomly selected civil engineering major is female

`=\text{ }(0.08x)/(0.17x)\text{ = 0.47}`

Therefore the probability that a randomly selected civil engineering major is female = 0.47.

STEP 2

The number of female students that major in civil engineering is

`(8)/(100)\text{ x X = 0.08}x`

The number of female students in the school=

`(55)/(100)\text{ x X = 0.55}x`

b) The probability that a randomly selected female student majors in civil

engineering

`(0.08x)/(0.55x)\text{ = 0.15}`

Therefore the probability that a randomly selected female student majors in civil

engineering = 0.15