Question

Write the equation -x+3y=6 in slope intercept form.. then graph the line described by the equation

Answer 1

Given the equation of a line

`-x+3y=6`

The slope-intercept form of a line is given as

`\begin{gathered} y=mx+c \\ \text{Where} \\ m\text{ is the slope of the line and} \\ c\text{ is the y-intercept of the line} \end{gathered}`

Hence to express the line -x + 3y = 6 in slope-intercept form, we need to isolate the variable y

`\begin{gathered} -x+3y=6 \\ \text{ Add x to both sides of the equation} \\ -x+x+3y=6+x \\ 3y=6+x \\ y=(x)/(3)+(6)/(3) \\ y=(x)/(3)+2 \end{gathered}`

The graph of the function is given by