Question

Need help on number 6. Have had tutors that can’t answer. Super precise.

Answer 1

Given

Mass of the three particles,

`\begin{gathered} m_1=7.3\text{ kg} \\ m_2=9.5\text{ kg} \\ m_3=9.7\text{ kg} \end{gathered}`

Their respective coordinates are:

`\begin{gathered} (x_1,y_1)=(3,-4) \\ (x_2,y_2)=(-11,4) \\ (x_3,y_3)=(8,1) \end{gathered}`

The angular velocity is

`\omega=21\text{ rad/s}`

To find

The angular momentum

Step-by-step explanation

Moment of inertia about the y-axis

`\begin{gathered} I=m_1x_1^2+m_2x_2^2+m_3x_3^2 \\ \Rightarrow I=7.3*3^2+9.5*(-11)^2+9.7*8^2 \\ \Rightarrow I=1836\text{ kgm}^2 \end{gathered}`

The angular momentum is

`\begin{gathered} L=I\omega \\ \Rightarrow L=1836*21=38556\text{ Js} \end{gathered}`

Conclusion

The angular momentum is B.38556 Js