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Consider the following functions.$(x) = x2 + 9 and g(x) = -x + 6Step 2 of 4: Find g(a)-f(a). Simplify your answer.Answer8(a)-f(a)

Consider the following functions.$(x) = x2 + 9 and g(x) = -x + 6Step 2 of 4: Find-example-1
User Dorla
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The functions are given as,


\begin{gathered} f(x)\text{ = x}^2+9 \\ g(x)\text{ = -x + 6} \end{gathered}

f(a) is calculated as,


f(a)\text{ = a}^2+9__\text{ \_\_\_\_\_\_\_\_\lparen1\rparen}_

g(a) is calculated as,


g(a)\text{ = -a + 6 \_\_\_\_\_\_\_\lparen2\rparen}

Subtracting equation (1) from (2),


\begin{gathered} g(a)\text{ - f\lparen a\rparen = \lparen-a+6\rparen- \lparen a}^2_+9) \\ g(a)\text{ - f\lparen a\rparen = -a + 6 - a}^2-9 \\ g(a)\text{ - f\lparen a\rparen= -a}^2\text{ - a - 3} \\ g(a)\text{ - f\lparen a\rparen= -\lparen a}^2+\text{ a + 3\rparen} \end{gathered}

Thus the required answer is,


g(a)\text{ - g\lparen a}\operatorname{\rparen}\text{=-\lparen a}^2\text{ + a + 3\rparen}

User Bdart
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