Answer:
The astronaut will be propelled towards the shuttle at the rate of 0.4 m/s.
Step-by-step explanation:
Given;
mass of the astronaut, m₁ = 95 kg
mass of the hammer thrown, m₂ = 2 kg
velocity of the hammer, v₂ = 19 m/s
let the recoil velocity of the shuttle = v₁
Apply the principle of conservation of linear momentum;
m₁v₁ = m₂v₂
v₁ = m₂v₂/m₁
v₁ = (2 x 19) / 95
v₁ = 0.4 m/s
Therefore, the astronaut will be propelled towards the shuttle at the rate of 0.4 m/s.