Question

Find the zeros of the following quadratic equation:y = x^2-3x-18A.) -3, -6B.) 3, -6C.) 3, 6D.) -3, 6

Answer 1

we have the quadratic equation

`y=x^2-3x-18`

using the formula

a=1

b=-3

c=-18

substitute given values

`x=(-(-3)(+_-)√(-3^2-4(1)(-18)))/(2(1))`
`x=(3(_(+\-))9)/(2)`

The values of x are

x=6 and x=-3

the answer is option D