The given sequence is
![\lbrace3,8,13,18,23,28,33,...\rbrace](https://img.qammunity.org/2023/formulas/mathematics/college/rek4a1aoyrfu5d7h2gaml07e10r6jj7rd9.png)
Since
8 - 3 = 5
13 - 8 = 5
23 - 18 = 5
Then it is an arithmetic sequence with common differences 5
We need to find
![\sum_{n\mathop{=}4}^7a_n](https://img.qammunity.org/2023/formulas/mathematics/college/kh0doyem23vbvnqe8iz5k6svb84bk9mv9o.png)
That means we need the sum of the terms from n = 4 to n = 7
The 4th term is 18
The 7th term is 33
Then the sum is
![\begin{gathered} S=18+23+28+33 \\ \\ S=102 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cqo79vv38o6apxvu93wgkg51t8z85lhe0n.png)
The answer is c