Question

The sum of consecutive integers 1,2,3.. n is given by the formula 2/2n(n+1) how many consecutive integers, starting with 1, must be added to get a sum 946?

Answer 1

Step-by-step explanation:

Given the sequence 1, 2, 3,..., n,

where;

`\begin{gathered} a_1=\text{first term}=1 \\ d=\text{common difference }=2-1=1 \end{gathered}`

Given the below formula for the sum of consecutive integers;

`S_n=(2)/(2n(n+1))`

Given 946, as the required sum, let's go-ahead and substitute it into the formula and cross multiply as seen below;

`\begin{gathered} \\ \\ \end{gathered}`