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Solve on the interval [0,27): 2 cscx -3 = -5 ОА. Зл 2 O 2T 4T B. 3.3 7 T 1 IT c O T O D. IS

Solve on the interval [0,27): 2 cscx -3 = -5 ОА. Зл 2 O 2T 4T B. 3.3 7 T 1 IT c O-example-1

1 Answer

7 votes

Answer:


x\text{ = }(3\pi)/(2)

Step-by-step explanation:

We want to get the value of x on the interval for which the identity holds true

We have this as follows:


\begin{gathered} \csc \text{ x = }\frac{1}{\sin \text{ x}} \\ \\ \frac{2}{\sin \text{ x}}\text{ = -5+3} \\ \\ \frac{2}{\sin \text{ x}}\text{ = -2} \\ \\ \sin \text{ x = -1} \\ \\ x\text{ = }\sin ^(-1)\text{ (-1)} \\ \\ x\text{ = }(3\pi)/(2) \end{gathered}

User Ahmed Ghrib
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