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Solve 4x^2-10x-36=0 using the quadratic formula

User Keplah
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1 Answer

5 votes

Solution:

Given the equation:


4x^2-10x-36=0\text{ ---- equation 1}

To solve using the quadratic formula, we have the solution of the quadratic equation:


y=ax^2+bx+c\text{ ---- equation 2}

to be


x=(-b\pm√(b^2-4ac))/(2a)\text{ ----- equation 3}

Comparing equations 1 and 2, we have


\begin{gathered} a=4 \\ b=-10 \\ c=-36 \end{gathered}

By substituting these values into equation 3, we have


\begin{gathered} x=(-(-10)\pm√((-10)^2-4(4*-36)))/(2(4)) \\ =(10\pm√(676))/(8) \\ =(10\pm26)/(8) \\ \Rightarrow x=(10+26)/(8)=(9)/(2) \\ or \\ \Rightarrow x=(10-26)/(8)=-2 \end{gathered}

Hence, the solution, using the quadratic formula, is


x=(9)/(2)\text{ or x=-2}

User Jgrocha
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